Posted by **Traci** on Sunday, February 20, 2011 at 9:42pm.

40 students live in a dormitory. 5 have swine flu. If 4 students are selected at random, what is the probability that 1 or 2 of the 4 have swine flu?

- Probability -
**drwls**, Sunday, February 20, 2011 at 10:36pm
Probability of 0: (35/40)(34/39)(33/38)(32/37) = 0.5729

Probability of 4: (5/40)*(4/39)*(3/38)*(2/37) = 120/2,193,360 = 0.000055

Probability of 1:

4*(35/40)*(34/39)*(33/38)*(5/37)= 0.3581

Probability of 2:

(4!/(2!*2!))(35/40)*(34/39)*(5/38)*(4*37)= 0.0651

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