Homework Help: algebra

Posted by Jam on Sunday, February 20, 2011 at 4:47pm.

A train can travel 280 miles in the same time that it takes a car to travel 140 miles. If the train's rate is 40 miles per hour faster than the cars, find the average for each.

algebra - Helper, Sunday, February 20, 2011 at 5:23pm
Distance D = Rate R * Time T
T = D/R

R = rate for car
R + 40 = rate for train
140/R = time for car
280/(R + 40) = time for train

Times are equal
280/(R + 40) = 140/R
Cross multiply and solve for R, rate for car

R + 40 = rate for train

Answer this Question

Related Questions

math - I need help to get started with writing the equation for the following ...
algebra 2 - I don't know how to do this the speed of train A is 18mph slower...
math - Train A is 12 mph slower than train B. Train A travels 230 miles in the ...
math - Train A is 12 mph slower than train B. Train A travels 230 miles in the ...
Algebra - The speed of train A is 6 mph slower than the speed of train B. Train ...
algebra - The speed of train A is 6 mph slower than the speed of train B. Train ...
algebra - the speed of train A is 8 mph slower than the speed of train B. Train ...
math - the speed of a train a is 6 mph slower than the speed of train b. train a...
math - The speed of a train A is 8mph slower than the speed of train B. Train A ...
Math - the speed of train A is 16 mph slower than the speed of train B. Train A...

For Further Reading

First Name:
School Subject:
Answer: