posted by Tichele on .
2.50 mL of ethyl acetate and 2.50 mL of distilled water are added to the 5.00 mL of 3 Molar HCl and the mixture is allowed to sit for a week. At the end of this time, 28.30 mL of 1.000 Molar NaOH was needed to titrate the solution. (The HCl was the same as used in 1a. This value was 3.44 Molar HCl)
A) How many millimoles of acetic acid were present at equilibrium?
B) How many millimoles of water were present at equilibrium?
C) How many millimoles of ethyl acetate were present at equilibrium?
I have no idea where to go with this for my lab and getting help on this section would most likely help me finish the lab. So any help would be greatly appreciated!