What volume of a 0.34M MgCI2 soultion is required to make 250ml of a 0.10M solution by dillution?
To calculate the volume of the 0.34M MgCl2 solution required to make 250ml of a 0.10M solution by dilution, we can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution
In this case, the initial solution is the 0.34M MgCl2 solution, with an unknown volume (V1). The final solution is the diluted 0.10M solution, with a volume of 250ml (V2).
Let's plug in the values we have:
(0.34M)(V1) = (0.10M)(250ml)
Now, rearrange the equation to solve for V1:
V1 = (0.10M)(250ml) / 0.34M
V1 = (0.10 * 250) / 0.34
V1 = 25 / 0.34
V1 ≈ 73.53 ml
Therefore, you would need approximately 73.53 ml of the 0.34M MgCl2 solution to make 250ml of a 0.10M solution by dilution.