points (3,6) and (-5,-2)
Slope m = (y2 - y1)/(x2 - x1)
m = (-2 - 6)/(-5 - 3)
m = -8/-8 = 1
Slope-intercept form of the equation,
y = mx + b,
where m = slope and b = y-intercept
To find the y-intercept, Use either point to substitute into the equation,
y = mx + b
P (3,6), m = 1
y = mx + b
6 = 1(3) + b
6 = 3 + b
b = 3
Therefore, the equation where m = 1 and b = 3 is,
y = 1x + 3
y = x + 3
Thanks! I'm covering maths classes so it's annoying not knowing how to explain and mark work
we are trying to find out how to use the equation to determine whether or not the point (-3,2) lies on this line?
the x-intercept and the y-intercept of the line in the first question and the kids have to show each step of their method clearly.
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