Posted by kia on Sunday, February 20, 2011 at 6:03am.
To arrive at the same PLACE, the second snowball must be launched at a complementary angle of 25 degrees.
The difference in the time of flight for those two launch angles is the required delay time, Tdelay.
Tdelay = 2 (Vsin65 - Vsin25)/g
= [(10 m/s)/9.8 m/s^2]*(0.4836)
= 0.49 seconds
A particular Ferris wheel (a rigid wheel rotating in a vertical plane about a horizontal axis) at a local carnival has a radius of 20.0 m and it completes 1 revolution in 9.84 seconds.
(a) What is the speed (m/s) of a point on the edge of the wheel?
Using the coordinate system shown, nd:
the (b) x component of the acceleration of point A at the top of
the wheel.
the (c) y component of the acceleration of point A at the top of the wheel
the (d) x component of the acceleration of point B at the bottom of the wheel.
the (e) y component of the acceleration of point B at the bottom of the wheel
the (f) x component of the acceleration of point C on the edge of the wheel.
the (g) y component of the acceleration of point C on the edge of the wheel
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