Posted by Patti on Saturday, February 19, 2011 at 11:21pm.
s is in Q1 (sin>0, cos>0)
so
cos(s)=1/3,
sin(s)=+√(1-(1/3)²)
=√(8/9)
tan(s)=√(8/9) / (1/3)
=√8
t is in Q4 (sin<0, cos>0)
sin(t)=-1/2
cos(t)=+√(1-(1/2)²)
=√(3/4)
tan(t)=(-1/2)/√(3/4)
=-1/√3
[rationalize by multiplying numerator and denominator by √3]
=-(√3)/3
Use the identity
tan(s+t)=(tan(s)+tan(t))/(1-tan(s)tan(t)) to calculate tan(s+t)
I get about 0.85.
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