Posted by mNoellb on Saturday, February 19, 2011 at 10:41pm.
A pressure cooker is shaped like a can
with a lid 25 cm in diameter. If the pressure
in the cooker can reach 3.0 atm, how much
force must the latches holding the lid onto the pot be designed to withstand?
I have F=PA
I have my P: 3.03 * 10^3 N/m^2
A=pi(.25 * 10^2m^2)^2
I'm not sure If I am doing it right.

Physics  drwls, Sunday, February 20, 2011 at 12:49am
3.0 atm is 3.04*10^5 N/m^2. There is also a pressure of 1 atm on the outside, so the latches only have to withstand a net pressure force of 2 atm = 2.03*10^5 N/m^2.
Your lid area is incorrect also. It is (pi/4)*D^2 = 4.91*10^2 m^2.

Physics  moi, Sunday, February 20, 2011 at 12:47pm
OH! well Thank you! My teacher seems to leave like .. most of that out.. geez!

Physics  mohanad, Thursday, April 3, 2014 at 4:22pm
F=P*A
A= Pi*r^2
A=Pi*(25/2)^2
A=0.04909 cm^2
Pgauge=Pabs 1 atm
p abs =P gauge+1
P abs= 4 atm
F= (0.04909 cm^2 * (1m^2)/(100cm)^2)*(4 atm*1.013*10^5 N/m^2)
F=1.99 N
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