The solubility of NaCl in water is 35.7g NaCl/100g H2O. Suppose that you have 500.0g of NaCl. What is the minimum volume of water you would need to dissolve it all? (Assume that de density of water is 1.0 g/mL.)
100 g H2O x (500/37.5) = g H2O needed.
Since the density is 1.0 g/mL, then grams H2O must be the same as the volume of water in mL.
how many kg does h2o have
How to find the number of grams of solute per 100.0 mL of pure water
Well, if we have 500.0g of NaCl, I would suggest finding a swimming pool instead of a water glass, my friend. But let's crunch some numbers for fun anyway!
To figure out the minimum volume of water needed, we need to convert the mass of NaCl to moles and use the stoichiometry to determine the number of moles of water required.
Since the molar mass of NaCl is approximately 58.44 g/mol, we can calculate the number of moles in 500.0g:
moles of NaCl = mass of NaCl / molar mass of NaCl
= 500.0g / 58.44 g/mol
≈ 8.56 mol
Now, if the solubility of NaCl in water is 35.7g NaCl/100g H2O, that means 100g of water can dissolve 35.7g of NaCl. We can set up a proportion to find the volume of water needed:
35.7g NaCl 100g H2O
---------- = ----------
8.56 mol x g H2O
Cross-multiplying and solving for x, we get:
x = (8.56 mol * 100g H2O) / 35.7g NaCl
≈ 23.96 g H2O
Since the density of water is 1.0 g/mL, the minimum volume of water needed would be approximately 23.96 mL.
To determine the minimum volume of water needed to dissolve 500.0g of NaCl, we first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is 23.0 g/mol + 35.5 g/mol = 58.5 g/mol.
Here's how to calculate the number of moles of NaCl:
moles = mass / molar mass
moles = 500.0g / 58.5 g/mol ≈ 8.55 mol
According to the given solubility of NaCl in water, the ratio of NaCl to water is 35.7g NaCl per 100g water. To determine the minimum volume of water needed, we can use the fact that the density of water is 1.0 g/mL. Since the solubility is given in grams per 100 grams of water, we can express the ratio as 0.357g NaCl per 1g water.
To find the minimum volume of water:
volume = mass of NaCl / (ratio of NaCl to water)
volume = 500.0g NaCl / 0.357 g NaCl per 1g water
volume ≈ 1399.72 mL
Therefore, the minimum volume of water needed to dissolve all 500.0g of NaCl is approximately 1399.72 mL.