Im working on a lab dealing with NRM of C3H8O2. carbons are 57.5 (q) , 60.1 (t), and 73.1 (t) i forget how to find the basic structure.
To determine the basic structure of a compound, you need to analyze the given information about the atoms present in the molecule. In this case, you have the NRM (Nominal Resolved Mass) values of three carbon atoms in the compound C3H8O2.
The NRM values you provided are 57.5 (q), 60.1 (t), and 73.1 (t). The letters 'q' and 't' represent the numbers for the relative abundance of the isotopes of carbon: q for carbon-12 (C-12) and t for carbon-13 (C-13).
To find the basic structure, you need to consider the possible combinations of these carbon atoms in the molecule. Since the sum of the carbon NRM values should equal the molecular weight of C3H8O2 (which you didn't provide), I will assume it is 76.1 g/mol (calculated by adding the atomic weights of carbon, hydrogen, and oxygen in the compound).
To find the combination of carbons that give a total NRM of 76.1, let's consider all possible combinations by substituting the given q and t values:
1. (q, q, q) - All three carbon atoms are carbon-12 (q).
NRM = 3 * 57.5 = 172.5
2. (q, q, t) - Two carbon-12 atoms (q) and one carbon-13 atom (t).
NRM = 2 * 57.5 + 1 * 60.1 = 175.1
3. (q, t, q) - One carbon-12 atom (q) and two carbon-13 atoms (t).
NRM = 1 * 57.5 + 2 * 60.1 = 177.7
4. (t, q, q) - One carbon-12 atom (q) and two carbon-13 atoms (t).
NRM = 1 * 57.5 + 2 * 60.1 = 177.7
5. (t, t, q) - Two carbon-12 atoms (q) and one carbon-13 atom (t).
NRM = 2 * 57.5 + 1 * 60.1 = 175.1
6. (t, q, t) - Two carbon-12 atoms (q) and one carbon-13 atom (t).
NRM = 2 * 57.5 + 1 * 60.1 = 175.1
Based on the calculations above, none of the combinations yield an NRM value of exactly 76.1. Therefore, the given data might not accurately represent the compound C3H8O2, or there could be additional elements or isotopes present.
I would recommend rechecking the data provided or providing more information to accurately determine the basic structure of the compound.