physics
posted by mNoellb .
As a woman walks, her entire weight is momentarily supported on the heel of one shoe. Calculate the pressure exerted on the floor by a highheel shoe worn by a 50kg woman if the heel has an area of 2.0cm^2. Express the pressure in newtons per square meter and atmospheres.
I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
M50 kg
g=9.8 m/sec^2
r^2 (2cm^2)^2
I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.
Thank you!

Heel pressure = (weight)/(heel area)
The heel area must be expressed as 2*10^4 m^2. The heel pressure is M*g/2*10^4 m^2
The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2. 
I get it now! lol Thank you!
(50 kg)(9.8 m/sec^2)
____________________
(2.0m *10^4)
=>
2.45 * 10^6 Nm or Pa