Posted by **mNoellb** on Saturday, February 19, 2011 at 6:16pm.

As a woman walks, her entire weight is momentarily supported on the heel of one shoe. Calculate the pressure exerted on the floor by a high-heel shoe worn by a 50-kg woman if the heel has an area of 2.0cm^2. Express the pressure in newtons per square meter and atmospheres.

I am using the formula :

P= F/A => F=mg A= 3.14(r^2)

M-50 kg

g=9.8 m/sec^2

r^2- (2cm^2)^2

I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.

Thank you!

- physics -
**drwls**, Saturday, February 19, 2011 at 6:26pm
Heel pressure = (weight)/(heel area)

The heel area must be expressed as 2*10^-4 m^2. The heel pressure is M*g/2*10^-4 m^2

The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2.

- physics -
**mNoellb**, Saturday, February 19, 2011 at 6:56pm
I get it now! lol Thank you!

(50 kg)(9.8 m/sec^2)

____________________

(2.0m *10^-4)

=>

2.45 * 10^6 N-m or Pa

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