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As a woman walks, her entire weight is momentarily supported on the heel of one shoe. Calculate the pressure exerted on the floor by a high-heel shoe worn by a 50-kg woman if the heel has an area of 2.0cm^2. Express the pressure in newtons per square meter and atmospheres.

I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
M-50 kg
g=9.8 m/sec^2
r^2- (2cm^2)^2
I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.
Thank you!

  • physics -

    Heel pressure = (weight)/(heel area)

    The heel area must be expressed as 2*10^-4 m^2. The heel pressure is M*g/2*10^-4 m^2
    The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2.

  • physics -

    I get it now! lol Thank you!

    (50 kg)(9.8 m/sec^2)
    (2.0m *10^-4)
    2.45 * 10^6 N-m or Pa

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