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March 26, 2017

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(4y^2)^5
__________
y ^-3

  • Algebra - ,

    Julie, because of formatting please type division problems as follows (using "/" for division).

    If this is your problem,
    ((4y^2)^5)/y^-3

    1024y^10/y^-3 = 1024y^13

    Subtract the exponents, 10 - (-3) = 13

    Or, 1024y^10/(1/y^3)
    Invert the denominator and multiply,
    1024y^10 * y^3 = 1024y^13

    Remember, y^-3 = 1/y^3

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