Posted by **Julie** on Saturday, February 19, 2011 at 5:20pm.

(4y^2)^5

__________

y ^-3

- Algebra -
**Helper**, Saturday, February 19, 2011 at 6:31pm
Julie, because of formatting please type division problems as follows (using "/" for division).

If this is your problem,

((4y^2)^5)/y^-3

1024y^10/y^-3 = 1024y^13

Subtract the exponents, 10 - (-3) = 13

Or, 1024y^10/(1/y^3)

Invert the denominator and multiply,

1024y^10 * y^3 = 1024y^13

Remember, y^-3 = 1/y^3

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