Posted by me on .
solve by elimination
5x+3y+5z=16
2x+5yz=26
x4y+2z=10

math 
Reiny,
1st  5(3rd) > 23y  5z = 66
2nd  2(3rd) > 13y  5z = 36
subtract those > 10y = 30
y = 3
back in 13y5z=36
39  5y = 36
5z = 75
z = 15
put y=3 and z=15 into the original 3rd and you are done.