Posted by **Julius ** on Saturday, February 19, 2011 at 2:37pm.

A student is skateboarding down a ramp that is 5.5 m long and inclined at 19° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 2.9 m/s. Neglect friction and find the speed at the bottom of the ramp.

- physics -
**drwls**, Saturday, February 19, 2011 at 4:47pm
Apply conservation of energy. Neglect the rotational kinetic energy of the wheels, which will make a small difference since the wheels weigh much less than the skateboarder.

(M/2)[V2^2 - V1^2] = M g deltaH

= M g *5.5 sin 19

V1 = 2.9 m/s

Cancel the M's and solve for V2, the final velocity.

V2^2 - (2.9)^2 = 2*9.81*1.791 = 35.13

V2^2 = 35.13 + 8.41

V2 = 6.60 m/s

- physics -
**Julius **, Saturday, February 19, 2011 at 4:51pm
thank you

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