Posted by ANNANYA on Saturday, February 19, 2011 at 9:18am.
A RIGHT ANGLED TRIANGLE ABC IS GIVEN,WHERE AB IS 5CM,AC IS 12CM,BC IS 13CM,AD IS AN ALTITUDE FROM A TO BC,FIND THE AREA OF THE TRIANGLE AND FIND AD ALSO.

MATHS,7TH CLASS  Reiny, Saturday, February 19, 2011 at 10:21am
area = (1/2)base x height
= (1/2)(5)(12) = 30
We could also consider BC as the base, then AD becomes the height
so (1/2)(13)(AD) = 30
AD = 2(30)/13
= 60/13

MATHS,7TH CLASS  Anonymous, Tuesday, February 23, 2016 at 9:55am
30cm and60\13

MATHS,7TH CLASS  Aryan singh, Tuesday, May 17, 2016 at 5:30am
your ans will may be wrong because height and base could not accept on those questions database

MATHS,7TH CLASS  Sk, Sunday, February 19, 2017 at 9:48am
Here, area=30
Ad=4.6

MATHS,7TH CLASS  SHivam, Sunday, February 19, 2017 at 9:50am
Ad=4.6
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