calc
posted by yoo on .
f(x)=3x^ln(x),
find f '(9).
i can't find the answer :(
I got 3x^lnx(((ln(lnx))/x)+ 1/lnx)

F(x) = 3X^ln(x).
F'(x) = (3lnx)(X^(lnx1),
F'(9) = (3*ln9)(9^(ln91),
F'(9) = (3*2.1972)(9^(2.19721),
F'(9) = (6.5917)(9^1.1972),
F'(9) = (6.5917)(13.8817),
F'(9) = 91.5040.