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July 23, 2014

July 23, 2014

Posted by **Anonymous** on Friday, February 18, 2011 at 3:39pm.

(x - y - 1)3 = x; (1, -1)

- Calculus 2nd Post please help -
**Reiny**, Friday, February 18, 2011 at 4:38pmI will assume your equation is

(x - y - 1)^3 = x

then 3(x-y-1)^2(1 - dy/dx) = 1

at the given point...

3(1+1-1)^2(1-dy/dx) = 1

3 - 3dy/dx = 1

dy/dx = 2/3

so now you have the slope m=2/3 and the point (1,-1)

Use the method you learned in grade 9 to find the equation of that line.

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