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January 30, 2015

January 30, 2015

Posted by **Anonymous** on Friday, February 18, 2011 at 1:03pm.

(b) How long does this trip around Mars take?

- physics -
**tchrwill**, Sunday, February 20, 2011 at 10:29amThe circular velocity required to orbit a planet derives from V = sqrt[µ/R] where µ = the gravitational constant of the planet and R = the radius(in feet) of the orbiting body around the planet.

For Mars,

µ = 1.512819x10^15 ft.^3/sec.^2

R = 2111 miles = 11,146,080 feet

Therefore, V = sqrt[1.512819x10^15/11,146,080] = 11,650 ft./sec. = 7,943mph.

The time, or period, to complete an orbit derives from

T = 2(Pi)sqrt[r^3/µ]

...= 2(Pi)sqrt[11,146,080^3/1.512819x10^15] = 6011sec. = 100.18 minutes.

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