Posted by Anonymous on Friday, February 18, 2011 at 1:03pm.
An astronaut on the surface of Mars fires a cannon to launch an experiment package, which leaves the barrel moving horizontally. Assume that the freefall acceleration on Mars is three eighths that on the Earth.(a) What must be the muzzle speed of the package so that it travels completely around Mars and returns to its original location?
(b) How long does this trip around Mars take?

physics  tchrwill, Sunday, February 20, 2011 at 10:29am
The circular velocity required to orbit a planet derives from V = sqrt[µ/R] where µ = the gravitational constant of the planet and R = the radius(in feet) of the orbiting body around the planet.
For Mars,
µ = 1.512819x10^15 ft.^3/sec.^2
R = 2111 miles = 11,146,080 feet
Therefore, V = sqrt[1.512819x10^15/11,146,080] = 11,650 ft./sec. = 7,943mph.
The time, or period, to complete an orbit derives from
T = 2(Pi)sqrt[r^3/µ]
...= 2(Pi)sqrt[11,146,080^3/1.512819x10^15] = 6011sec. = 100.18 minutes.
Answer This Question
Related Questions
 physics  An astronaut on the surface of Mars fires a cannon to launch an ...
 science  the acceleration of gravity on the surface of Mars is m/s squared. if ...
 Physics  An astronaut wearing a spacesuit can jump 0.5 m vertically at the ...
 physics  You are on Mars and would like to send a probe into space so that it ...
 Physics  The freefall acceleration on Mars is 3.7 m/s2. (a) What length ...
 physics  The freefall acceleration on Mars is 3.7 m/s2. (b)What length of ...
 physics  The freefall acceleration on Mars is 3.7 m/s2. (b)What length of ...
 physics  Mars Rover When the Mars rover was deployed on the surface of Mars in ...
 physics  Meteorites from Mars Several meteorites found in Antarctica are ...
 Physics Help please  The freefall acceleration on Mars is 3.7 m/s2. (a) What ...
More Related Questions