Posted by **Catherine** on Thursday, February 17, 2011 at 9:15pm.

Find k for which the limit below exists, and find the limit.

lim x->1 (2x^2 + kx +4)/(x-1)

Please show me how to do both procedures. Thanks

- Calculus Please Help -
**bobpursley**, Thursday, February 17, 2011 at 9:21pm
well, if the limit exists, then in the numerator you have to have (x-1).

so if (2+k+4) is approaching zero, then

k=-6

lim x>1 (2x^2-6x+4)/(x-1)= lim 2(x^2-3x+2)/(x-1)=lim 2(x-1)(x-2)/(x-1)=

lim x>1 (2(x-2))=2*-1=-2

check that

## Answer this Question

## Related Questions

- Calculus 3 - Find the limit, if it exists, or show that the limit does not ...
- Calculus 3 - Find the limit, if it exists, or show that the limit does not exist...
- Calculus - Find if the limit exists. lim tan(x)/x x->0 Please show how you ...
- Calculus - I have two similar problems that I need help completing. Please show ...
- Calculus - Find the positive integers k for which lim ->0 sin(sin(x))/x^k ...
- calculus help please - hi what is lim as x reaches one of the function x/LN(x) ...
- calculus - (a) Find the number c such that the limit below exists. Limit as x ...
- calculus please help - lim y→−1 (sqrt(y^2+8)-3)/y+3 find limit if it...
- Calculus. Limits. Check my answers, please! :) - 4. lim (tanx)= x->pi/3 -(...
- Calculus - Find the limit. lim x-->1 (x^3)-1/((5x^2)+2x-7) Please show steps.

More Related Questions