Posted by Catherine on Thursday, February 17, 2011 at 9:15pm.
Find k for which the limit below exists, and find the limit.
lim x>1 (2x^2 + kx +4)/(x1)
Please show me how to do both procedures. Thanks

Calculus Please Help  bobpursley, Thursday, February 17, 2011 at 9:21pm
well, if the limit exists, then in the numerator you have to have (x1).
so if (2+k+4) is approaching zero, then
k=6
lim x>1 (2x^26x+4)/(x1)= lim 2(x^23x+2)/(x1)=lim 2(x1)(x2)/(x1)=
lim x>1 (2(x2))=2*1=2
check that
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