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July 25, 2014

July 25, 2014

Posted by **Catherine** on Thursday, February 17, 2011 at 9:15pm.

lim x->1 (2x^2 + kx +4)/(x-1)

Please show me how to do both procedures. Thanks

- Calculus Please Help -
**bobpursley**, Thursday, February 17, 2011 at 9:21pmwell, if the limit exists, then in the numerator you have to have (x-1).

so if (2+k+4) is approaching zero, then

k=-6

lim x>1 (2x^2-6x+4)/(x-1)= lim 2(x^2-3x+2)/(x-1)=lim 2(x-1)(x-2)/(x-1)=

lim x>1 (2(x-2))=2*-1=-2

check that

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