Posted by Catherine on Thursday, February 17, 2011 at 9:15pm.
well, if the limit exists, then in the numerator you have to have (x-1).
so if (2+k+4) is approaching zero, then
k=-6
lim x>1 (2x^2-6x+4)/(x-1)= lim 2(x^2-3x+2)/(x-1)=lim 2(x-1)(x-2)/(x-1)=
lim x>1 (2(x-2))=2*-1=-2
check that
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