How many grams of magnesium oxide are formed when 13.5 L of oxygen gas, measured at STP, completely reacts with magnesium metal according to the following reaction?

i got .496 g
but i know that like way off

2Mg+O2>>2MgO

n=PV/RT=13.5/22.4*moles of O2, so you will get twice that in MgO, or 13.5/11.2 moles MgO, so what mass of MgO is that number of moles?

To determine the number of grams of magnesium oxide formed when oxygen gas reacts with magnesium metal, we need to use stoichiometry.

First, let's write the balanced chemical equation for the reaction:

2 Mg + O2 --> 2 MgO

From the balanced equation, we can see that 2 moles of magnesium react with 1 mole of oxygen gas to produce 2 moles of magnesium oxide.

To solve this problem, we'll follow these steps:

1. Convert the given volume of oxygen gas to moles using the ideal gas law.
2. Use the stoichiometry of the balanced equation to find the moles of magnesium oxide.
3. Convert the moles of magnesium oxide to grams using the molar mass.

Step 1: Convert the given volume of oxygen gas to moles.

Given:
Volume of oxygen gas = 13.5 L
Temperature = STP (Standard Temperature and Pressure)

At STP, 1 mole of any gas occupies 22.4 liters. Therefore, we can calculate the number of moles of oxygen gas using the ideal gas law:

moles of oxygen gas = volume (L) / molar volume at STP

moles of oxygen gas = 13.5 L / 22.4 L/mol

Step 2: Use the stoichiometry of the balanced equation.

From the balanced equation, we know that 2 moles of magnesium react with 1 mole of oxygen gas to produce 2 moles of magnesium oxide. Therefore, the ratio between moles of oxygen gas and moles of magnesium oxide is 1:2.

moles of magnesium oxide = moles of oxygen gas * (2 moles of magnesium oxide / 1 mole of oxygen gas)

moles of magnesium oxide = (13.5 L / 22.4 L/mol) * (2 mol MgO / 1 mol O2)

Step 3: Convert moles of magnesium oxide to grams.

To do this, we need to know the molar mass of magnesium oxide. Magnesium (Mg) has a molar mass of 24.31 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.

The molar mass of magnesium oxide (MgO) is calculated as follows:

Molar mass of MgO = (molar mass of Mg) + (molar mass of O)

Molar mass of MgO = 24.31 g/mol + 16.00 g/mol

Now, multiply the moles of magnesium oxide by its molar mass to get the mass in grams:

mass of magnesium oxide = moles of magnesium oxide * molar mass of magnesium oxide

mass of magnesium oxide = (moles of magnesium oxide) * (40.31 g/mol)

Substitute the value of moles of magnesium oxide from step 2 into the equation:

mass of magnesium oxide = (13.5 L / 22.4 L/mol) * (2 mol MgO / 1 mol O2) * (40.31 g/mol)

Calculating this equation will give you the correct answer for the number of grams of magnesium oxide formed when 13.5 L of oxygen gas, measured at STP, reacts with magnesium metal.