Posted by **stacy** on Thursday, February 17, 2011 at 8:09pm.

A rock is thrown from a cliff top at 18m/s, 25 degrees above the horizontal. It lands on the beach 4.2 seconds later.

a) What is the height of the cliff?

b) Hor far from the base of the cliff did the rock land?

- physics -
**bobpursley**, Thursday, February 17, 2011 at 8:10pm
vertical veloctiy: 18sin25

Hf=hi+viv*t-1/2 g t^2

hf=0, hi=unknown,viv=18sin25, t=4.2 solve for hi.

horizontal distance? 18cos25*4.2

- physics -
**stacy**, Thursday, February 17, 2011 at 8:13pm
great, thank you so much!

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