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March 6, 2015

March 6, 2015

Posted by **stacy** on Thursday, February 17, 2011 at 8:09pm.

a) What is the height of the cliff?

b) Hor far from the base of the cliff did the rock land?

- physics -
**bobpursley**, Thursday, February 17, 2011 at 8:10pmvertical veloctiy: 18sin25

Hf=hi+viv*t-1/2 g t^2

hf=0, hi=unknown,viv=18sin25, t=4.2 solve for hi.

horizontal distance? 18cos25*4.2

- physics -
**stacy**, Thursday, February 17, 2011 at 8:13pmgreat, thank you so much!

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