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April 17, 2014

April 17, 2014

Posted by **Catherine** on Thursday, February 17, 2011 at 7:24pm.

(a) s(t) = 3t^2, Find v(-1).

(b) s(t) = 1/t , Find v(2).

(c) s(t) = square root of t, Find v(1).

The answers that I got were the following...

a)3

b)1/2

c)1

I did them another way and the answers I got were

a)-6

b) -(1/4)

c) I didn't really get any answers here.

Please tell me which answers are right or if any of them are right...

- Calculus (pleas help I really need to check this) -
**Reiny**, Thursday, February 17, 2011 at 7:51pma) -6

b) -1/4

c) 1/2

- Calculus (pleas help I really need to check this) -
**Ralph**, Thursday, February 17, 2011 at 7:52pma) -6

b) - 1/4

c) 1/2 = square root of t is

1/2(square root of t)

- Calculus (pleas help I really need to check this) -
**Catherine**, Thursday, February 17, 2011 at 8:07pmThank you very much for the clarification, could you explain to me how you got 1/2 in c please??

- Calculus (pleas help I really need to check this) -
**Reiny**, Thursday, February 17, 2011 at 8:20pms(t) = √t = t(1/2)

s '(t) = (1/2)t^(-1/2) = 1/(2√t)

s '(1) = 1/(2√1) = 1/2

- Calculus (pleas help I really need to check this) -
**Catherine**, Thursday, February 17, 2011 at 9:44pmCould you please tell me how to do it evaluating the limt algebraically? I'm trying to do it and I can't get it....

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