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September 25, 2016
Posted by **Phil** on Thursday, February 17, 2011 at 3:12pm.

- Calculus -
**Reiny**, Thursday, February 17, 2011 at 5:34pmThe direction vector of the given line is (2,-1,3) and a point on it is (0,3,1)

So using that point and the additional given point (1,2,-2)

yields a second direction vector of (1,-1,-3)

So we need a normal to these two direction vectors, which is the cross-product of (2,-1,3) and (1,-1,-3)

I got this normal to be (6,9,-1)

(I will assume you know how to find the cross-product)

The equation of the plane is

6x + 9y - z = k

subbing in the given point (1,2,-2)

6 + 18 + 2 = k = 26

equation of plane : 6x + 9y - z = 26