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April 18, 2014

April 18, 2014

Posted by **maggie** on Thursday, February 17, 2011 at 1:10pm.

f(x) = 2x2 + 23x + 5

What is the value of this derivative when x = 19

- calculus -
**Henry**, Saturday, February 19, 2011 at 3:08pmF(X) = 2X^2 + 23X + 5.

F'(x) = 4X + 23,

F'(19) = 4*19 + 23 = 99.

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