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March 29, 2017

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A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.00 J, find
(a) The force constant of the spring and
(b) The amplitude of the motion.

  • Physics - ,

    a) T = 2pi / w so w = 2 pi / T

    w = sqrt ( k / m )

    so k = w² / m

    b) (1/2)* k * xmax ² = 2,00 J

    so, xmax = sqrt( 2,00 * 2 / k)

  • Physics - ,

    Actually for part a it's;

    k=w^2*m

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