400 cm3 of 0.5mol/dm3 hydrochloric acid was reacted with 5g of magnesium oxide. Calculate the mass of reacted oxide? Show the steps and thq..
Henry
I need help
Well, well, well, looks like we have a chemistry question here! Time to put on my lab coat and clown nose. Let's get calculating!
First, we need to find the number of moles of hydrochloric acid (HCl) used. To do that, we'll use the formula:
Number of moles = Volume (in dm3) x Concentration (in mol/dm3)
Given that the volume is 400 cm3, we need to convert it to dm3 by dividing it by 1000:
Volume = 400 cm3 / 1000 = 0.4 dm3
Now, we can calculate the number of moles of HCl:
Number of moles HCl = 0.4 dm3 x 0.5 mol/dm3 = 0.2 moles HCl
Next, we need to determine the number of moles of magnesium oxide (MgO) that reacted with the HCl. The balanced chemical equation for the reaction between HCl and MgO is:
2HCl + MgO -> MgCl2 + H2O
Looking at the equation, we can see that it takes two moles of HCl to react with one mole of MgO. Since we have 0.2 moles of HCl, we'll have half as many moles of MgO:
Number of moles MgO = 0.2 moles HCl / 2 = 0.1 moles MgO
Finally, to find the mass of the reacted MgO, we'll use its molar mass. The molar mass of magnesium oxide (MgO) is approximately 40 grams/mole (24 grams/mole for Mg + 16 grams/mole for O):
Mass of reacted MgO = Number of moles MgO x Molar mass MgO
= 0.1 moles MgO x 40 grams/mole
= 4 grams
So, the mass of the reacted MgO is 4 grams.
Keep up the chemistry clowning!
First, let's determine the number of moles of hydrochloric acid:
Volume of hydrochloric acid = 400 cm^3 = 400/1000 = 0.4 dm^3.
Number of moles of hydrochloric acid = 0.5 mol/dm^3 * 0.4 dm^3 = 0.2 mol.
According to the balanced chemical equation:
MgO + 2HCl -> MgCl2 + H2O
It shows that the stoichiometric ratio between magnesium oxide and hydrochloric acid is 1:2. Therefore, 1 mole of MgO reacts with 2 moles of HCl.
From the stoichiometry, we can conclude that the number of moles of MgO reacted is twice the number of moles of HCl, which is:
Number of moles of MgO reacted = 2 * 0.2 mol = 0.4 mol.
To calculate the mass of reacted magnesium oxide, we need to know the molar mass of magnesium oxide (MgO).
Molar mass of MgO = atomic mass of magnesium (24.31 g/mol) + atomic mass of oxygen (16.00 g/mol) = 40.31 g/mol.
Mass of reacted MgO = number of moles of MgO * molar mass of MgO = 0.4 mol * 40.31 g/mol = 16.124 g.
Therefore, the mass of the reacted magnesium oxide is 16.124 grams.
To calculate the mass of the reacted magnesium oxide, we need to use the stoichiometry of the balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium oxide (MgO).
The balanced equation for the reaction is:
2HCl + MgO -> MgCl2 + H2O
The stoichiometry of this reaction tells us that 2 moles of hydrochloric acid react with 1 mole of magnesium oxide to produce 1 mole of magnesium chloride and 1 mole of water.
Given:
Volume of HCl solution = 400 cm3 = 0.4 dm3
Concentration of HCl solution = 0.5mol/dm3
Mass of magnesium oxide (MgO) = 5g
Step 1: Calculate the amount of hydrochloric acid (HCl):
Amount of HCl (in moles) = Concentration of HCl x Volume of HCl solution
= 0.5mol/dm3 x 0.4 dm3
= 0.2 moles
Step 2: Use the stoichiometry of the balanced equation to find the amount of reacted magnesium oxide (MgO):
From the balanced equation, we know that 2 moles of HCl react with 1 mole of MgO. Therefore, the amount of MgO can be calculated as follows:
Amount of MgO (in moles) = (Amount of HCl / 2)
= (0.2 moles / 2)
= 0.1 moles
Step 3: Calculate the molar mass of MgO:
The molar mass of magnesium oxide (MgO) can be calculated by adding the atomic masses of magnesium (Mg) and oxygen (O) together.
Molar mass of MgO = Atomic mass of Mg + Atomic mass of O
= (24.31 g/mol) + (16.00 g/mol)
= 40.31 g/mol
Step 4: Calculate the mass of reacted magnesium oxide (MgO):
Mass of MgO = Amount of MgO x Molar mass of MgO
= 0.1 moles x 40.31 g/mol
≈ 4.03 g
Therefore, the mass of reacted magnesium oxide (MgO) is approximately 4.03 grams.