Posted by mayrel on Thursday, February 17, 2011 at 10:13am.
Each horse pulls with a force of 700 N at an angle of 10° with the centerline of the canal.
700N acts at an angle of 10° to the direction of motion of barge and contributes only a part of the force.
F*sin(10)to the opposite side of angle (along lateral direction) and F*cos(10) to the adjacent side of angle (along centerline of canal)
Net Force from 2 horses = 2*[700*cos(10)]
= 1378.73 N
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