A)HOW FAR IS THEBOAT FROM THE BASE OF THE CLIFF?

B) IF AFTER 10MIN THE BOAT HAS SAILED 1KM AWAY FROM THE CLIFF WHAT IS THE NEW ANGLE OF DEPRESSION OF THE BOAT ?
C) HOW FAR IS THE BOAT FROM THE BASE OF THE CLIFF AFTER 45MIN?

I will assume that your previous post of

"FROM THE TOP OF A VERTICAL CLIFF 200M SEA LEVEL A BOAT WAS SIGHTED AT ANGLE OF 26CELSIUS ? "
and this post constitute one and the same question.
Secondly, I will assume that you meant an
"angle of 26 degrees" , not celsius, which is a measure of temperature.

Looks like tan26 = 200/x or
x = 200/tan26 = appr.410.1 m

b) so if the new distance is 410.1+1000 or 1410.1 m, let the new angle be theta
tan(theta) = 200/1410.1
theta = appr. 8.1 degrees

c) from b) we know the rate is 1000/(10/60) m/h or 6000 m/h
so in 45 minutes the boat would have gone another (45/60)(6000) = 4500 m

Add this to the origianl 410.1 and repeat steps of b)

To answer these questions, we need some additional information. We need the height of the cliff and the initial angle of depression of the boat from the top of the cliff.

A) To determine the distance of the boat from the base of the cliff, we would need to know the height of the cliff and the initial angle of depression of the boat. The angle of depression is the angle formed between a horizontal line and the line of sight from the top of the cliff to the boat.

B) After 10 minutes, if the boat has sailed 1 km away from the cliff, we can calculate the new angle of depression using trigonometry. We would need the height of the cliff and the initial angle of depression to determine this.

C) To find the distance of the boat from the base of the cliff after 45 minutes, we would need the speed of the boat. With the speed, we can calculate the distance covered by the boat in 45 minutes. However, we also need the initial distance between the boat and the cliff to calculate the final distance.

In summary, we need the height of the cliff, the initial angle of depression, and either the speed of the boat or the initial distance between the boat and the cliff to answer these questions accurately.