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March 30, 2017

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Joe has a collection of nickels and dimes that is worth $6.05 if the number of dimes was double and the number of nickels was decreased by 10 the value of the coins would be $9.85 how many nickels and dimes does he have?

  • Math - ,

    case 1:
    let the number of nickels be n
    let the number of dimes be d
    5n + 10d = 605
    n + 2d = 121

    case 2
    number of nickels ---> n - 10
    number of dimes ---> 2d
    5(n-10) + 10(2d) = 985
    5n - 50 + 20d = 985
    5n + 20d = 1035
    n + 4d = 207

    subtract them
    2d = 86
    d = 43 then n = 35

    He has 43 dimes and 35 nickels

  • Math - ,

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