Math
posted by Lisa on .
Joe has a collection of nickels and dimes that is worth $6.05 if the number of dimes was double and the number of nickels was decreased by 10 the value of the coins would be $9.85 how many nickels and dimes does he have?

case 1:
let the number of nickels be n
let the number of dimes be d
5n + 10d = 605
n + 2d = 121
case 2
number of nickels > n  10
number of dimes > 2d
5(n10) + 10(2d) = 985
5n  50 + 20d = 985
5n + 20d = 1035
n + 4d = 207
subtract them
2d = 86
d = 43 then n = 35
He has 43 dimes and 35 nickels 
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