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Posted by **Lisa** on Wednesday, February 16, 2011 at 11:40pm.

- Math -
**Reiny**, Wednesday, February 16, 2011 at 11:51pmcase 1:

let the number of nickels be n

let the number of dimes be d

5n + 10d = 605

n + 2d = 121

case 2

number of nickels ---> n - 10

number of dimes ---> 2d

5(n-10) + 10(2d) = 985

5n - 50 + 20d = 985

5n + 20d = 1035

n + 4d = 207

subtract them

2d = 86

d = 43 then n = 35

He has 43 dimes and 35 nickels

- Math -
**Anonymous**, Friday, November 2, 2012 at 8:47pmburblrshkash ahhhrq

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