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February 1, 2015

February 1, 2015

Posted by **Anonymous** on Wednesday, February 16, 2011 at 8:41pm.

∫ sec^3x tanx dx

I let u=tanx

took derivative..

du=sec^2x dx

..now what??

- Calculus -
**helper**, Wednesday, February 16, 2011 at 9:18pmsec^3 x tan x dx

| = integral symbol

Rewrite as

| sec^2 x sec x tan x dx

u = sec x

du = sec x tan x

| u^2 du

1/3 u^3 + C

Substitute back in, u = sec x

1/3 sec^3 x + C

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