Posted by **Anonymous** on Wednesday, February 16, 2011 at 8:41pm.

Evaluate the indefinite integral.

∫ sec^3x tanx dx

I let u=tanx

took derivative..

du=sec^2x dx

..now what??

## Answer this Question

## Related Questions

- Calc - Hello im trying to integrate tan^3 dx i have solved out the whole thing ...
- Calc - Hello im trying to integrate tan^3 dx i have solved out the whole thing ...
- calculus - Did I do this problem right? Find the first and second derative-...
- calculus (check my work please) - Not sure if it is right, I have check with the...
- Calculus - Integration - Hello! I really don't think I am understanding my calc ...
- calculus - Integration - evaluate ∫sec^7 x tanx dx
- Calculus - find the derivative of f(x)=tanx-4/secx I used the quotient rule and ...
- Pre-Cal - Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x...
- calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...
- Calculus. I need help! - Evaluate the indefinite integral (a.)∫√(...

More Related Questions