# trig

posted by
**Amy** on
.

cos θ = (2√(2)) / (3)

sin θ = - (1/3)

then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?

posted by
**Amy** on
.

cos θ = (2√(2)) / (3)

sin θ = - (1/3)

then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?