Posted by
**Amy** on
.

cos θ = (2√(2)) / (3)

sin θ = - (1/3)

then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?

Sunday

March 26, 2017
Posted by
**Amy** on
.

cos θ = (2√(2)) / (3)

sin θ = - (1/3)

then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?

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