Posted by Marie on Wednesday, February 16, 2011 at 4:57pm.
log[2](3)+log[2](x)=log[2](5)+log[2](x-2)
=>
log[2](3*x) = log[2](5*(x-2))
=>
3x=5(x-2)
=>
5x-3x=5*2
=>
2x=10
=>
x=5
Check by putting x into the original equation and see if it balances.
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