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January 30, 2015

January 30, 2015

Posted by **Marie** on Wednesday, February 16, 2011 at 4:57pm.

log[2](3)+log[2](x)=log[2](5)+log[2](x-2)

1. Solve equation by setting up algebraically.

2. Use appropriate properties of Logarithm to reduce the number of logarithmic terms to only one.

3. Solve logarithmic equation.

- calculus -
**MathMate**, Wednesday, February 16, 2011 at 5:22pmlog[2](3)+log[2](x)=log[2](5)+log[2](x-2)

=>

log[2](3*x) = log[2](5*(x-2))

=>

3x=5(x-2)

=>

5x-3x=5*2

=>

2x=10

=>

x=5

Check by putting x into the original equation and see if it balances.

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