Please help me?
y=log(x+1)
a. Write the equation as an exponential equation and solve for x.
b. Switch the variables in your answer to part a (Change x to y and vice versa). Write the new expression.
Y = log(X + 1).
a. 10^y = X + 1,
X = 10^y - 1.
b. Y = 10^x - 1.
Of course! I can help you with that.
a. Writing the equation as an exponential equation involves applying the exponentiation function with base 10 to both sides of the equation. The logarithm and exponentiation functions are inverses of each other. So, by raising both sides of the equation to the power of 10, we get:
10^y = x + 1
To solve for x, we need to isolate it. We can do this by subtracting 1 from both sides of the equation:
10^y - 1 = x
Therefore, the equation expressed as an exponential equation is: x = 10^y - 1.
b. To switch the variables in the answer from part a, we will change x to y and vice versa. So, in the expression x = 10^y - 1, we replace x with y and y with x:
y = 10^x - 1
Now, the new expression is y = 10^x - 1.
I hope that helps! Let me know if you have any further questions.