Posted by **mary** on Wednesday, February 16, 2011 at 12:46pm.

How do I find the indefinite integral of h(u)=sin^2(1/5u) this is one fifth u. Does it involve double angle formulas? Thanks.

## Answer this Question

## Related Questions

- calculus please help - I posted this below but had no response. I would ...
- Calc BC - 1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2...
- Calculus - Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of...
- MATH - 1.)Find the exact solution algebriacally, if possible: (PLEASE SHOW ALL ...
- trig integration - s- integral endpoints are 0 and pi/2 i need to find the ...
- calculus - Evaluate the indefinite integral. integral of 8 sin^4 x cos x dx
- calculus - Using an integration formula,what is the indefinite integral of (sign...
- calculus - Evaluate the indefinite integral. integral of 4e^(4x)sin[e^(4x)]dx
- trig - Given that sin (pi/10)=(sqrt(5)-1)/4, use double-angle formulas to find ...
- Math 2nd question - Express as a single sine or cosine function (note: this is ...

More Related Questions