Posted by Joella on Wednesday, February 16, 2011 at 11:14am.
Solve by elimination methodthanks fro checking my work
2x + 3y= 2 multiply this equation by 2= 4x + 6y = 4
4x2y = 28
4x + 6y = 4
4x 2y = 28
8y = 32
y = 4
2x + 3(4) = 2
2x + 12 = 2
2x + 212
2x = 10
x = 5
solution = (5,4)

Algebra IIPlease check my solution  Kate, Wednesday, February 16, 2011 at 11:21am
you're on the right track but when you tried to subtract the 2 eq you only subtracted the first term, but left the others' signs the same.
It should look like this:
4x+6y=4
4x+2y=28 now add the two eq together and redo the work you did before. if you have more questions just ask!

Algebra IIPlease recheckPlease check my solution  Joella, Wednesday, February 16, 2011 at 11:47am
when I wrote the 4x 2y = 28
I forgot to put the next step which was 4x + 2y = 28
but isn't the rest of my steps the same still because when I subtracted those they became 8y = 32 and the rest Thanks for respondingI'm not sure if this isn't right stillI think the answer is correct minus the one step I forgot to write

Algebra IIPlease recheck your correctionPlease check my solution  Joella, Wednesday, February 16, 2011 at 11:56am
I think I see where you mistook what I wroteI'm doing the elimination method and subtracting the equations so the new equations were
4x + 6y = 4 after I multiplied first equation by 2
minus 4x 2y = 28 and so the 4x becomes , the 2y becomes positive and the 28 becomes positive, correct
Thank you

Algebra IIPlease check my solution  Kate, Wednesday, February 16, 2011 at 12:29pm
You're right. I'm sorry. When I saw the missed step, I stopped looking at the rest of the work. You are correct.
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