Posted by Z32 on .
A freezer has a coefficient of performance of 6.30. It is advertised as using 486 kWh/yr. Note: One kilowatthour (kWh) is an amount of energy equal to running a 1kW appliance for one hour.
a) On average, how much energy does it use in a single day?
I got 4.79 x 10^6 J
(b) On average, how much energy does it remove from the refrigerator in a single day?
I got 30177000 J
Now I'm stuck on this part:
What maximum mass of water at 17.1°C could the freezer freeze in a single day? (The latent heat of fusion of water is 3.33 x 10^5 J/kg, and its specific heat is 4186 J/kg · °C.) answer in kg

Physics 
drwls,
Compute the amount of heat that must be removed to freeze one kg of water that is initially 17.1 C. Assume the ice temperature stays at 0 C, once it is formed (although this is not necessarily the case)
That would be 3.35*10^5 J + 17.1*4186 = 4.046*10^5 J/kg
Finally, divide your computed heat removal by that heat per mass number. 
Physics 
Z32,
Thank you!