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October 31, 2014

October 31, 2014

Posted by **Jena** on Tuesday, February 15, 2011 at 7:57pm.

find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-8, -6) and (x2, y2) = (0, 0)

slope 0-(-6)/0-(-8)= 3/4

how would I write it?

y=3/4x or y=3/4x+0 ?

- intermediate algebra-check my answer -
**helper**, Tuesday, February 15, 2011 at 8:03pmy = ax + b

m = 3/4

y = 3/4 x + b

You need to find b for this equation.

Substitute one of the given points into your equation and solve for b.

Then use that b value for your equation.

- intermediate algebra-check my answer -
**Jena**, Tuesday, February 15, 2011 at 8:10pmI don't get a value for b, What am I missing?

- intermediate algebra-check my answer -
**helper**, Tuesday, February 15, 2011 at 8:25pmYou were given the points,

(x1, y1) = (-8, -6) and (x2, y2) = (0, 0)

y = 3/4 x + b

Use one of the given points, for example,

(-8, -6)

Solve for b

-6 = 3/4(-8) + b

b = 0

Therefore, the equation is

y = 3/4 x + 0

y = 3/4 x

I guess I miss-understood you. I didn't realize that you had already found the b value to be zero. (Since you didn't state that b = 0 originally). I shouldn't have assumed.

- intermediate algebra-check my answer -
**Jena**, Tuesday, February 15, 2011 at 9:38pmOk thanks

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