If the price of electrical energy is $0.10 per kilowatt*hour, what is the cost of using electrical energy to heat the water in a swimming pool (12.0m*9.00m*1.5m) from 15 to 27 degrees Celcius?

To calculate the cost of using electrical energy to heat the water in a swimming pool, we need to consider the following steps:

1. Determine the volume of the pool:
Volume = Length x Width x Depth
Volume = 12.0m x 9.00m x 1.5m
Volume = 162 cubic meters

2. Calculate the change in temperature:
ΔT = Final Temperature - Initial Temperature
ΔT = 27°C - 15°C
ΔT = 12°C

3. Calculate the amount of energy required to heat the water:
Energy = Mass x Specific Heat Capacity x ΔT
But since we don't have the mass of water, let's use the density of water instead.
Density of Water = 1000 kg/m³

Mass = Density x Volume
Mass = 1000 kg/m³ x 162 m³
Mass = 162,000 kg

Energy = Mass x Specific Heat Capacity x ΔT
Specific Heat Capacity of Water = 4.18 J/g°C
Convert kg to grams:
Energy = (162,000 kg x 1000 g/kg) x 4.18 J/g°C x 12°C
Energy = 81,336,000,000 J

4. Convert energy from Joules to kilowatt-hours (kWh):
1 kWh = 3.6 x 10^6 J
Energy (kWh) = Energy (J) / (3.6 x 10^6 J/kWh)
Energy (kWh) = 81,336,000,000 J / (3.6 x 10^6 J/kWh)
Energy (kWh) = 22,593.3 kWh

5. Calculate the cost of using electrical energy:
Cost = Energy (kWh) x Cost per kWh
Cost = 22,593.3 kWh x $0.10/kWh
Cost = $2,259.33

Therefore, the cost of using electrical energy to heat the water in the swimming pool from 15 to 27 degrees Celsius would be $2,259.33.

To determine the cost of using electrical energy to heat the water in a swimming pool, we need to calculate the amount of energy used and then multiply it by the cost of electrical energy per kilowatt-hour.

First, let's calculate the volume of the swimming pool:

Volume = length * width * height
Volume = 12.0m * 9.00m * 1.5m
Volume = 162 cubic meters

Next, let's calculate the change in temperature:

Change in temperature = final temperature - initial temperature
Change in temperature = 27°C - 15°C
Change in temperature = 12°C

Now, we need to calculate the amount of energy required to heat the water using the formula:

Energy = volume * specific heat capacity * change in temperature

Where the specific heat capacity of water is 4.18 J/g·°C and 1 kilowatt-hour is equivalent to 3,600,000 Joules.

Specific heat capacity (c) = 4.18 J/g·°C
1 kilowatt-hour = 3,600,000 Joules

First, let's convert the volume from cubic meters to liters:

Volume = 162 cubic meters * 1000 liters/cubic meter
Volume = 162,000 liters

Now, we need to calculate the amount of energy in Joules:

Energy = volume * specific heat capacity * change in temperature * 1000 grams/liter
Energy = 162,000 liters * 4.18 J/g·°C * 12°C * 1000 grams/liter

Next, we convert the energy from Joules to kilowatt-hours:

Energy (kilowatt-hours) = Energy (Joules) / 3,600,000 Joules/kilowatt-hour

Finally, we calculate the cost of using electrical energy:

Cost = Energy (kilowatt-hours) * price per kilowatt-hour

Please provide the price per kilowatt-hour to proceed with the calculation.