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April 20, 2014

April 20, 2014

Posted by **Melanie** on Tuesday, February 15, 2011 at 6:08pm.

1) Which of the following is an equation of a vertical line?

F. 4x + 5y = 0

G. -4 = 16x

H. 3y = -9

I. 4x + 5y = -1

2) Which equation is the equation of a line that passes through (-10, 3) and is perpendicular to y = 5x - 7?

A. y = 5x + 53

B. y = - 1/5x - 7

C. y = - 1/5x + 1

D. y = 1/5x + 5

It would also be greatly appreciated if you told me how you got your answer. Thanks! :)

- Math -
**MathMate**, Tuesday, February 15, 2011 at 6:25pmHints:

1. The equation of a vertical line has the y-term absent, since it is not possible to calculate y for a given x.

2. The slope of L: y=5x-7 has a slope of 5.

The slope of a line perpendicular to L has a slope m such that 5*m=-1, or m=-1/5.

Also, if the line L1 passes through the point P(-10,3), then by substituting x=-10 and solving for y, we should get y=3.

Post your answers for confirmation if you wish.

- Math -
**Melanie**, Tuesday, February 15, 2011 at 6:51pmFor 1, I got G and for the second one I got B. are they correct?

- Math -
**MathMate**, Tuesday, February 15, 2011 at 6:57pmG is correct for 1.

For 2,

if I substitute -10 in y = - 1/5x - 7 ,

I get y=(-1/5)*(-10)-7=2-7=-5, we're looking for 3.

Give it another try. You're close.

- Math -
**Melanie**, Tuesday, February 15, 2011 at 7:02pmUmmm is it C?

- Math -
**MathMate**, Tuesday, February 15, 2011 at 7:22pmYou do not seem very sure about it. Can you demonstrate why it is, or it is not C?

- Math -
**Melanie**, Sunday, February 20, 2011 at 8:06pmI'm sure about it now :) Thank you for your help. I know it is C because once I put in the x and y axis into the equation, I multiplied 1/5 with -10 then added one and the result was three that's how I knew it was C :)

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