Write the equation of the line:
The points are at (-8,-6) and (0,0).
The line passing through these two points has a y-intercept of 0 since it passes through the origin.
The slope is -6-0/-8-0=3/4
How would I finish this? Thanks
To find the equation of a line in slope-intercept form (y = mx + b), we need to substitute the values of the slope (m) and the y-intercept (b) into the equation.
In this case, we already have the value of the slope (m = 3/4) and the y-intercept (b = 0). So, the equation of the line is:
y = (3/4)x + 0
Simplifying this, we get:
y = (3/4)x
Therefore, the equation of the line passing through the points (-8,-6) and (0,0) is y = (3/4)x.