Wednesday
October 22, 2014

Homework Help: Chemistry

Posted by Julie on Tuesday, February 15, 2011 at 2:49pm.

I need to find out what the total acid concentration is in Kool-Aid.
If 23.3 mL of 0.1043M NaOH neutralize a 60 mL solution of Kool-Aid (10 mL) and water (50 mL), what is the total concentration in a 10.00 mL aliquot of Kool-Aid? If you prepared a standard 250 mL serving by mixing a packet of Kool-Aid with 2 L of water, what would the total acid concentration be?

What I've probably calculated incorrectly so far...
23.3 mL NaOH x 0.1043 M NaOH = 2.430 mMol NaOH. = 1 mole OH = 2.430 mMol H+.
2.430 mMol H+/60 mL = 0.040 M H+.

For the total acid concentration in a 10 mL sample,
(0.040 x 0.06)/0.01 = 0.24 M

For the total acid concentration in a 250 mL serving,
(0.040 x 0.06)/2 = 1.2 x 10^-3

The balanced equation is:
5 citric acid + 2 ascorbic acid + 17 NaOH -> 5 citrate ion + 2 ascorbic acid + 17 H20.

The equation of interest is: H+ + OH- -> H2O

Any help would be appreciated.
Thanks

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