in a triangle the middle length side is 3 more than the shortest side, and the longest side is double the middle lenght side the perimeter of the triangle is 45cm find the lenghts of the side

u do the math

Shortest side = X cm.

Middle side = (X + 3)cm.
Longest side = 2(x + 3) = (2X + 6)cm.

X + (X + 3) + (2X + 6) = 45cm,
4X + 9 = 45,
4X = 45 - 9 = 36,

X = 9cm = Shortest side.
X + 3=9 + 3 = 12cm=Middle length side.
2X + 6 = 18 + 6 = 24cm = Longest side.

To solve this problem, we can start by assigning variables to the lengths of the sides of the triangle. Let's call the shortest side x.

According to the given information, the middle length side is 3 more than the shortest side. So, the middle length side can be expressed as (x + 3).

The longest side is stated to be double the middle length side. Therefore, the longest side can be expressed as 2(x + 3), which simplifies to 2x + 6.

We know that the perimeter of a triangle is the sum of the lengths of all three sides. In this case, the perimeter is given as 45 cm. So, we can set up the following equation:

x + (x + 3) + (2x + 6) = 45

Simplifying the equation, we get:

4x + 9 = 45

Next, we can solve for x by isolating the variable:

4x = 45 - 9
4x = 36
x = 36 / 4
x = 9

Now that we have found the value of x, we can substitute it back into our expressions for the other sides to find their lengths.

Shortest side: x = 9 cm
Middle length side: x + 3 = 9 + 3 = 12 cm
Longest side: 2x + 6 = 2(9) + 6 = 18 + 6 = 24 cm

Therefore, the lengths of the sides of the triangle are 9 cm, 12 cm, and 24 cm.