Posted by JayCee on Tuesday, February 15, 2011 at 12:25am.
a block of mass 2.50 kg rests on a ramp. if the coefficient of static friction between the block and ramp is 0.350, what maximum angle can the ramp make with the horizontal before the block starts to slip down?

physics please please please please please  Henry, Wednesday, February 16, 2011 at 9:28pm
F = 2.50 * 9.8 = 24.5N @ A deg.
Fp = 24.5*sinA = Force parallel with plane.
Fv = 24.5*cosA = Force perpendicular to
plane.
uFv = 0.35Fv = Force of friction.
Fp  0.35Fv = ma,
a = 0(block at rest),
Fp 0.35Fv = 0,
Fp = 0.35Fv,
24.5*sinA = 0.35*24.5*cosA,
Divide both sides by 24.5:
sinA = 0.35*cosA
Divide both sides by cosA:
sinA / cosA = 0.35,
sinA / cosA = TanA,
TanA = 0.35,
A = 19.3deg.

physics please please please please please  abdirahman, Saturday, April 9, 2016 at 12:48pm
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