Posted by **JayCee** on Tuesday, February 15, 2011 at 12:25am.

a block of mass 2.50 kg rests on a ramp. if the coefficient of static friction between the block and ramp is 0.350, what maximum angle can the ramp make with the horizontal before the block starts to slip down?

- physics please please please please please -
**Henry**, Wednesday, February 16, 2011 at 9:28pm
F = 2.50 * 9.8 = 24.5N @ A deg.

Fp = 24.5*sinA = Force parallel with plane.

Fv = 24.5*cosA = Force perpendicular to

plane.

uFv = 0.35Fv = Force of friction.

Fp - 0.35Fv = ma,

a = 0(block at rest),

Fp -0.35Fv = 0,

Fp = 0.35Fv,

24.5*sinA = 0.35*24.5*cosA,

Divide both sides by 24.5:

sinA = 0.35*cosA

Divide both sides by cosA:

sinA / cosA = 0.35,

sinA / cosA = TanA,

TanA = 0.35,

A = 19.3deg.

- physics please please please please please -
**abdirahman**, Saturday, April 9, 2016 at 12:48pm
answer

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