what is the total area of the four walls of a rectangular room 4 meters long by 5.5 meters wide by 3 meters high?

is it 4 times 5.5? then times four since there are 4 walls? 88m squared?

your data does not make a lot of sense

If the four walls are each 4 m long, where does the 5.5 m wide come in?

The way I interpret the question is that one pair of opposite walls are 4 m wide and the other pair of opposite walls are 5.5 m wide
so you would have
2(4x3) + 2(5.5x3) = 24 + 33 = 57 m^2

In your calculation you have completely ignored the fact that the room is 3 m high.

To calculate the total area of the four walls of a rectangular room, you need to find the sum of the areas of each individual wall.

First, let's find the area of the two longer walls:
- The length of the room is 4 meters, and the height is 3 meters. So, the area of one longer wall is 4 meters * 3 meters = 12 square meters.
Since there are two longer walls, their combined area is 2 * 12 square meters = 24 square meters.

Now, let's find the area of the two shorter walls:
- The width of the room is 5.5 meters, and the height is 3 meters. So, the area of one shorter wall is 5.5 meters * 3 meters = 16.5 square meters.
Again, since there are two shorter walls, their combined area is 2 * 16.5 square meters = 33 square meters.

Finally, to find the total area of all four walls, you add the areas of the longer walls and the areas of the shorter walls:
Total area = Area of longer walls + Area of shorter walls
Total area = 24 square meters + 33 square meters
Total area = 57 square meters.

Therefore, the total area of the four walls of the given rectangular room is 57 square meters, not 88 square meters as you initially suspected.

thanks. i was a bit confused of why there were 3 numbers that is why i ignored the 3m part.. Thanks! :D

Was that the way the question was worded in the textbook ???

yes it was. it also said ignore all doors and windows..