Posted by Kim on Monday, February 14, 2011 at 10:21pm.
Mike, Nicole and Kim, do please use the same pseudonym in your posts, because it helps to improve continuity.
We do not do repetitive exercises, that's your duty and privilege.
However, if each question brings up a new facet of the subject, we're glad to help/explain each.
For this problem, make a bijection onto the number of digits of the licence plate. That means that there is a one-to-one correspondence each way, so the count of one problem is the same as the count of the other.
B: 4
M: 4
E: 2 out of 10
H: 4 or S: 4 ≡ 4+4=8
Since she is not allowed to take two of the same Elective courses, there are only (10-1)=9 choices for the second.
So the total number of courses is
4²*10*9*8
Related Questions
math - A student planning her curriculum for the upcoming year must select one ...
math 12 - In Lisa's first-year college program she must take nine courses ...
Math - A college freshman must take a science course, a humanities course, an ...
math - A student of MA101 is preparing a course schedule for the next semester. ...
MATH - A student of MA101 is preparing a course schedule for the next semester. ...
math - A college offers nine different psychology courses,four different history...
math 121 - 1. A college offers three different psycology . courses, four ...
Calculus - Greetings, This is a question about selecting courses for my semester...
Probability - HCC offers 21 Humanities courses. If all students must take 2 of ...
statistics - Let x be the number of courses for which a randomly selected ...
For Further Reading
