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April 16, 2014

April 16, 2014

Posted by **Kim** on Monday, February 14, 2011 at 10:21pm.

- math -
**MathMate**, Monday, February 14, 2011 at 10:36pmMike, Nicole and Kim,

*do*please use the same pseudonym in your posts, because it helps to improve continuity.

We do not do repetitive exercises, that's your duty and privilege.

However, if each question brings up a new facet of the subject, we're glad to help/explain each.

For this problem, make a bijection onto the number of digits of the licence plate. That means that there is a one-to-one correspondence each way, so the count of one problem is the same as the count of the other.

B: 4

M: 4

E: 2 out of 10

H: 4 or S: 4 ≡ 4+4=8

Since she is not allowed to take two of the same Elective courses, there are only (10-1)=9 choices for the second.

So the total number of courses is

4²*10*9*8

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