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November 26, 2014

November 26, 2014

Posted by **Meg** on Monday, February 14, 2011 at 9:46pm.

I thought you might do three cases with the three values of p in the hint, plugging them into p^2+2. In two of the cases you get a p^2+2=3a (a some integer) form but for p=3k you do not. Am I approaching this wrong?

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**MathMate**, Monday, February 14, 2011 at 10:13pmThe third case is the simplest, because

3|3k

so you're done!

- math -
**MathMate**, Monday, February 14, 2011 at 10:14pmOn the other hand, since it is a prime ≠ 3, so in fact, the third case does not even arise.

- math -
**SHAKEERA**, Tuesday, February 22, 2011 at 8:11pmNO

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