Friday

December 19, 2014

December 19, 2014

Posted by **Meg** on Monday, February 14, 2011 at 9:46pm.

I thought you might do three cases with the three values of p in the hint, plugging them into p^2+2. In two of the cases you get a p^2+2=3a (a some integer) form but for p=3k you do not. Am I approaching this wrong?

- math -
**MathMate**, Monday, February 14, 2011 at 10:13pmThe third case is the simplest, because

3|3k

so you're done!

- math -
**MathMate**, Monday, February 14, 2011 at 10:14pmOn the other hand, since it is a prime ≠ 3, so in fact, the third case does not even arise.

- math -
**SHAKEERA**, Tuesday, February 22, 2011 at 8:11pmNO

**Answer this Question**

**Related Questions**

IB HL Math - I need to that if there is better way to prove the following: I am ...

Math - Prove that if p is prime and 1 <= k < p that p divides p!/(k!(p-k...

Discrete Math - Prove that if a and b are integers with a not equal to zero and ...

maths --plse help me.. - Let a,b,c be positive integers such that a divides b^2...

urgent -plsee - Let a,b,c be positive integers such that a divides b^2 , b ...

maths --plse help me.. - Let a,b,c be positive integers such that a divides b^2...

maths - Let a,b,c be positive integers such that a divides b^2 , b divides c^2 ...

maths - Let a,b,c be positive integers such that a divides b^2 , b divides c^2 ...

math - the sum of the digits of a two digit prime number is substracted from the...

Math - Which of the following is a prime #? a.2 b.19 c.37 d.51 e.67 I choose 2. ...