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December 20, 2014

December 20, 2014

Posted by **jay** on Monday, February 14, 2011 at 8:11pm.

- math -
**MathMate**, Monday, February 14, 2011 at 8:57pmFor this period, all years begin with 2, so they must end with a 2.

The next digit is "free", i.e. we have a free choice of all the digits between 0 and 9.

The third digit has to be the same as the second, if the number has to be a palindrome.

So how many palindromic year are there between 2000 and 3000?

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