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August 27, 2014

August 27, 2014

Posted by **Sidney** on Monday, February 14, 2011 at 3:29pm.

[Sixth root of 27]+[cube root of x] = 6/(3-[square root of 3]

- math -
**Reiny**, Monday, February 14, 2011 at 3:46pm27^(1/6) + x^(1/3) = 6/(3 - √3)

(3^3)^(1/6) + x^(1/3) = 6/(3 - √3)[(3+√3)/(3+√3)]

3^(1/2) + x^(1/3) = 3 + 2√3

x^(1/3) = 3 + √3)

x = (3+√3)^3

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