a right triangle whose hypotenuse is h mm long is rotated about one of its legs to generate a circular cone.find the radius and altitude of the cone of greatest volume.

To find the radius and altitude of the cone of greatest volume, we need to apply mathematical optimization techniques. Let's start by establishing some relationships and equations:

1. Consider a right triangle with legs of lengths a and b, and a hypotenuse of length h.
2. The radius of the generated cone, denoted as r, is the distance from the tip of the cone to the center of the circular base.
3. The altitude of the cone, denoted as l, is the height of the cone from the tip to the center of the circular base.

We know that the hypotenuse of the right triangle is related to the legs using the Pythagorean theorem:

a² + b² = h²

Furthermore, we know that the height of the cone is related to the legs and the radius using the formula for similar triangles:

l / a = r / b

Now, let's solve for a and b in terms of h:

From the Pythagorean theorem:
a² = h² - b²
a = √(h² - b²)

From the formula for similar triangles:
l = (r * a) / b

Next, we want to express the volume of the cone, V, in terms of a single variable, either a or b:

V = (1/3) * π * r² * l

Substituting the expressions for a and l derived earlier:
V = (1/3) * π * r² * [(r * √(h² - b²)) / b]
V = (π / 3) * r³ * √(h² - b²) / b

Now, we need to find the values of b and r that maximize the volume of the cone. To do this, we can take the derivative of V with respect to b, set it to zero, and solve for the critical values:

dV/db = 0

Differentiating, we get:
(π / 3) * (3r² * √(h² - b²) - 2r³ * b / √(h² - b²)) / b² = 0

Simplifying, we have:
3r² * √(h² - b²) - (2r³ * b) / √(h² - b²) = 0
3r² * (h² - b²) - 2r³ * b = 0
3r²h² - 3r²b² - 2r³b = 0

To solve this equation, we could use algebraic techniques, but it becomes rather complex. Therefore, it is convenient to solve this equation numerically using optimization software or tools like calculus optimization algorithms.

Once the value of b is determined, we can substitute it back into the expression for a to find its value. Finally, the radius r and altitude l can be calculated using the derived formulas for r and l in terms of a and b.

This method enables us to find the radius and altitude of the cone with the greatest volume using mathematical optimization techniques.