Posted by Anonymous on Monday, February 14, 2011 at 12:21am.
Convert pH 3.0 to (H^+) using pH = -log(H^+).
Convert pH 5.6 to (H^+).
Divide 1st by the 2nd to find the ratio acid/normal
do I just use the moles of H+?
No, the pH needs to be converted to H^+ using the inverse log
Example:
ph = -log[H^+] = 3.0
log [H^+] = -3.0
[H^+] = inv log (3.0)
10^(-3.0)
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